Let's return to our list of equations.
- y = 4x + 3
- y = 4x1/2 + 3
- y = 4x - 2z +3
- y = 10/x
- y = 2x
- lny = 4lnx
- y = 3 + 4x2
- lnQ = -2lnP +1.5lnY
The first equation is by far the simplest. If we programmed excel to give
us one column with 1 through 40 and the next column to give me 4 times the
number in column 1 plus 3, then we would produce the following Table and Graph.
[For cell B4 we= would have the equation: = 4*A4 + 3.
The Table
|
x |
y |
|
0 |
3 |
|
1 |
7 |
|
2 |
11 |
|
3 |
15 |
|
... |
... |
|
30 |
123 |
|
31 |
127 |
This graph of this equation signifies a relationship between x and y such
that every time x increases (decreases) by 1, y increases (decreases) by 4. If
we were looking at the graph, the relationship between changes in x and changes
in y show up in the slope which would be 4.
The Graph
In the equation form, the slope (rate of change) appears as a parameter,
in this case the coefficient of x. The other parameter in the equation is 3
which tells us that when x=0, y is equal to 3. In a graph, this would be the y
intercept-the value of y when x equals 0.
y = 4x + 3
If we compare equations 1 and 7 we find there is only one difference. In
equation 1 the variables y and x are raised to the first power (1), while in the
second equation x is raised to the second power (2). This is a significant
difference. At this point you should be able to recognize equations where the
variables are raised only to the first power. These are called linear equations and possess certain desirable properties.
The most obvious property is the fact that the rate at which y changes for any
change in x is independent of the value of x. In the linear equation, if we are
at x = 1 and move to x = 2, y increases by 4. The rate of change Dy/Dx =
(11-7)/(2-1) = 4. If we begin at x = 30, however, and move to x = 31, the rate
of change (Dy/Dx) = (127-123)/(31-30) = 4/1 = 4.
One can conclude from this simple example that when you have a linear
equation the following is true:
Dy/Dx =a
The rate at which x causes y to change is equal to the coefficient of x.
As we will see many times in this section, we can interpret this relationship as
one equation with three unknowns. Using the 'laws' of algebra, we can rewrite
this equation in the following two ways - each providing us with a different
variable on the left hand side of the = sign.
Dy = Dx*a
Dx = Dy/a
The first of these equations can be used to answer questions such as; how
much will y increase if x increases by 3? if x decreases by 4? In the case where
the coefficient was 4, x would increase by 12 when y increased by 3. If on the
other hand you happened to know that y increased by 12, you would know that x
must have increased by 3. You could answer this easily by referring to the
second form of the equation.
Before we leave our discussion of linear equations, let's return to the
list of equations and see if there are any other linear equations. The secret is
the exponent for the variables must be equal to 1. The fourth equation looks
promising, but you will note that X is in the denominator so we could rewrite it
as y = 10*X-1 so its exponent is really -1. Equation 3, meanwhile,
does satisfy our condition for a linear relationship, the only difference is
that y depends on two exogenous variables, x and z. The nature of the
relationship is identical to that which we discussed for the first equation. In
the linear equation, if we are at x = 1 and z = 2 and move to x = 2, then y
increases by 4. The rate of change Dy/Dx = (7-3)/(2-1) = 4. If we begin at x =
30, however, and move to x = 31, the rate of change (Dy/Dx) = (123-119)/(31-30)
= 4/1 = 4. Once again the coefficient of the variable gives us the slope of a
graph and the rate of change between y and x.
Similarly, the coefficient of z indicates the rate at which y changes when
z changes. In equation 6, y will change 2 for every one unit change in z. In
fact, you can see this in the table above. You note that as you move across one
row you are comparing the values of y, for a given value of x, as z changes from
0 to 2. For example, if x = 3 and z = 0, then y = 15. If you hold x constant at
3 and allow z to increase to 2, the value of y decreases to 11. In this
situation Dy/Dz = (11-15)/(2-0) = -4/2 = -2, which is the coefficient of z.
|
x |
z=0 |
x |
z=2 |
|
0 |
3 |
0 |
-1 |
|
1 |
7 |
1 |
3 |
|
2 |
11 |
2 |
7 |
|
3 |
15 |
3 |
11 |
|
31 |
123 |
31 |
119 |
|
33 |
127 |
33 |
123 |
Now let's move on to a discussion of nonlinear
relationships.